Answer:
Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below. Please see the file attached below to know the diagram.
Explanation:
There is the following solution that satisfies all requirements indicated on statement:
Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below.
[tex]R = \frac{(12\,\Omega)\cdot (4\,\Omega)}{12\,\Omega+4\,\Omega}+3\,\Omega[/tex]
[tex]R = 6\,\Omega[/tex]
Which observes all design requirements.
