Answer: 0.5 moles are present in 17.0 g of [tex]H_{2}O_{2}[/tex] .
Explanation:
Number of moles present in a substance is the given mass divided by molar mass of the substance.
As the given mass of [tex]H_{2}O_{2}[/tex] is 17.0 g and its molar mass is 34 g/mol.
Hence, number of moles present in given 17.0 g of [tex]H_{2}O_{2}[/tex] is as follows.
No. of moles = [tex]\frac{mass}{molar mass}[/tex]
= [tex]\frac{17.0 g}{34 g/mol}[/tex]
= 0.5 moles
Therefore, 0.5 moles are present in 17.0 g of [tex]H_{2}O_{2}[/tex] .
