Given that,
The vertices of a rectangle are (–1, 1), (3, 1), (–1, –4), and (3, –4).
To find,
The perimeter of the rectangle.
Solution,
Let the points are :
A(–1, 1), B(3, 1), C(3, –4) and D(–1, –4)
Let's find AB and BC using distance formula :
[tex]AB=\sqrt{(3-(-1))^2+(1-1)^2} \\\\=4\ \text{units}[/tex]
[tex]BC=\sqrt{(3-3)^2+(-4-1)^2} \\\\=5\ \text{units}[/tex]
The perimeter of a rectangle = 2(sum of two adjacent sides)
= 2(AB+BC)
= 2(4+5)
= 18 units
So, the perimeter of the rectangle is 18 units.
