Respuesta :
Answer: The ratio of number of hydroxide ions to iodide ions is 2 : 1.
Explanation:
The chemical equation for the oxidation of iodide ion is oxidized to hypoiodite ion by permanganate follows:
[tex]2MnO_4^-+I^-+H_2O\rightarrow 2MnO_2(s)+IO_3^{-}+2OH^{-}[/tex]
According to mole concept:
1 mole of a substance contains [tex]6.022\times 10^{23}[/tex] number of particles
Moles of iodide ions = 1 mole
Number of iodide ions = [tex](1\times 6.022\times 10^{23}[/tex]
Moles of hydroxide ions = 2 mole
Number of hydroxide ions = [tex](2\times 6.022\times 10^{23}[/tex]
Taking the ratio of number of hydroxide ions and number of iodide ions are as follows:
[tex]\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{(2\times 6.022\times 10^{23})}{(1\times 6.022\times 10^{23})}\\\\\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{2}{1}[/tex]
Hence, the ratio of number of hydroxide ions to iodide ions is 2 : 1.
