Answer:
[tex]P_2 - P_1 = 1.8 * 10^4\ Pa[/tex]
Explanation:
Given
[tex]Height (h) = 1.70m[/tex]
Required
Determine the difference in the blood pressure from feet to top
This is calculated using Pascal's second law.
The second law is represented as:
[tex]P_2 = P_1 + pgd[/tex]
Subtract P1 from both sides
[tex]P_2 - P_1 = pgd[/tex]
Where
[tex]p = blood\ density = 1.06 * 10^3kg/m^3[/tex]
[tex]g = acceleration\ of\ gravity = 9.8N/kg[/tex]
[tex]d =height = 1.70m[/tex]
P2 - P1 = Blood Pressure Difference
So, the expression becomes:
[tex]P_2 - P_1 = 1.06 * 10^3 * 9.8 * 1.70[/tex]
[tex]P_2 - P_1 = 17659.6Pa[/tex]
[tex]P_2 - P_1 = 1.8 * 10^4\ Pa[/tex]
Hence, the difference in blood pressure is approximately [tex]1.8 * 10^4\ Pa[/tex]
