Answer:
502.9 nm
Explanation:
Energy to break to the bond of carbon-iodine is not given assuming it to be 238KJ/mol
we know that
ΔE= hυ
also, υ= c/λ
therefore λ = hc/ΔE
[tex]= \frac{6.626\times10^{-34}\times3\times10^8}{238\times10^3}\\=0.08352\times10^{-29} m mol[/tex]
also, 1 mol = 6.022×10^23 atoms or molecules
[tex]\lambda= 0..08352\times10^{-29}\times6.022\times10^{23}\\=502.9 \times10^{-9}m\\=502.9 nm[/tex]
