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Answer:

1.38x10⁻⁴ M

Explanation:

First, we calculate the pOH of the solution, using the given pH:

  • pOH = 14 - pH
  • pOH = 14 - 10.44
  • pOH = 3.56

Now we calculate the concentration of OH⁻, using the pOH:

  • pOH = -log[OH⁻]
  • [OH⁻] = [tex]10^{-pOH}[/tex] = 2.75x10⁻⁴ M

Following the reaction Ca(OH)₂ → Ca⁺² + 2OH⁻, we divide [OH⁻] by 2 to calculate [Ca(OH)₂]:

  • [Ca(OH)₂] = 2.75x10⁻⁴ M / 2
  • [Ca(OH)₂] = 1.38x10⁻⁴ M

The concentration of the calcium hydroxide in the solution is 1.38 * 10⁻⁴ M

pH:

pH is calculated using the expression:

[tex]pH = - log [H_3O^+][/tex]

Given:

pH of the solution = 10.44

  • Calculation of pOH of the solution, using the given pH:

[tex]pOH = 14 - pH\\\\pOH = 14 - 10.44\\\\pOH = 3.56[/tex]

  • Calculation for concentration of OH⁻, using the pOH:

[tex]pOH = -log[OH^-]\\\\[OH^-] = 2.75* 10^{-4} M[/tex]

  • From the reaction:

Ca(OH)₂ → Ca⁺² + 2OH⁻

The concentration of OH⁻ is then divided by 2 according to the given reaction.

[tex][Ca(OH)_2] = \frac{2.75*10^{-4}M}{2}\\\\[Ca(OH)_2] = 1.38*10^{-4}M[/tex]

Thus, the concentration of the calcium hydroxide in the solution is 1.38 * 10⁻⁴ M.

Find more information about pH here:

brainly.com/question/13557815