What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of 10.0 meters in 8.0 seconds

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Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

[tex] P = \frac{W}{t} [/tex]

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

[tex] W = F*d [/tex]

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

[tex] F = mg = 400 kg*9.81 m/s^{2} = 3924 N [/tex]

Hence, the average power is:

[tex] P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W [/tex]                    

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!                  

The average power developed by a motor as it lifts the mass is 4,900 W.

The given parameters:

  • mass lifted, m = 400 kg
  • distance traveled, d = 10 m
  • time of motion, t = 8.0 s

The average power developed by a motor as it lifts the mass is calculated as follows;

[tex]P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{400 \times 9.8 \times 10}{8} \\\\P = 4,900 \ J/s[/tex]

Thus, the average power developed by a motor as it lifts the mass is 4,900 W.

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