Answer:
We know that the measure of each side is:
5.2cm to 1 decimal place.
Then we can assume that the error is 0.05cm (half of the second decimal place).
With this, the interval of the length of each side will be:
(5.2cm - 0.05cm) = 5.15cm (as the minimum)
(5.2cm + 0.05cm) = 5.25cm (as the maximum)
Then the interval is (5.15cm, 5.25cm)
2) We know that the perimeter of a square of sidelength L is:
P = 4*L
In this case, the minimum perimeter will be if we choose the smallest sidelength, this is:
P = 4*5.15cm = 20.6cm
And the maximum perimeter can be:
P = 4*5.25cm = 21cm
Then the interval is: (20.6cm, 21cm)
Here we can see that the error for the perimeter is 0.2cm, which is equal to 4 times the error of the length of a side (0.05cm) , as expected.
