contestada

A quantity of gas has a pressure of 1.39 atm and a volume of 6.95 L. What is the
volume of this gas when the pressure is changed to 740 mm Hg?

Respuesta :

Answer:

The volume of the quantity of gas when the pressure changes to 740 mm Hg is approximately 9.92 L

Explanation:

The properties of the quantity of gas are;

The initial pressure of the gas, P₁ = 1.39 atm

The initial volume of the given volume of gas, V₁ = 6.95 L

The final pressure of the quantity of gas, P₂ = 740 mmHg

Boyle's Law states that at constant temperature, the pressure, P, of a given mass of gas is inversely proportional to its volume, V

Mathematically Boyle's Law can be written as follows;

[tex]P \propto \dfrac{1}{V}[/tex]

Therefore, we have;

P₁·V₁ = P₂·V₂

Where;

V₂ = The final volume of the quantity of gas when the pressure changes to 740 mm Hg

[tex]\therefore V_2 = \dfrac{P_1 \cdot V_1}{P_2}[/tex]

By substituting the known values, we have;

[tex]V_2 = \dfrac{1.39 \ atm \times 6.95 \ L}{740 \ mmHg} = \dfrac{1.39 \ atm \times 6.95 \ L}{0.973521 \ atm} = 9.92159459459 \ L \approx 9.92 \ L[/tex]

The final volume of the quantity of gas when the pressure changes to 740 mm Hg = V₂ ≈ 9.92 L