Answer:
The volume of the quantity of gas when the pressure changes to 740 mm Hg is approximately 9.92 L
Explanation:
The properties of the quantity of gas are;
The initial pressure of the gas, P₁ = 1.39 atm
The initial volume of the given volume of gas, V₁ = 6.95 L
The final pressure of the quantity of gas, P₂ = 740 mmHg
Boyle's Law states that at constant temperature, the pressure, P, of a given mass of gas is inversely proportional to its volume, V
Mathematically Boyle's Law can be written as follows;
[tex]P \propto \dfrac{1}{V}[/tex]
Therefore, we have;
P₁·V₁ = P₂·V₂
Where;
V₂ = The final volume of the quantity of gas when the pressure changes to 740 mm Hg
[tex]\therefore V_2 = \dfrac{P_1 \cdot V_1}{P_2}[/tex]
By substituting the known values, we have;
[tex]V_2 = \dfrac{1.39 \ atm \times 6.95 \ L}{740 \ mmHg} = \dfrac{1.39 \ atm \times 6.95 \ L}{0.973521 \ atm} = 9.92159459459 \ L \approx 9.92 \ L[/tex]
The final volume of the quantity of gas when the pressure changes to 740 mm Hg = V₂ ≈ 9.92 L