Respuesta :
Answer: 4.91 kJ
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c_l\times (T_(f,l)-T_(i,l))+m\imes L+m\times c_v\times T_(f,v)-T_(i,v)[/tex]
Q = Heat absorbed = ?
m= mass of mercury = 48.5 g = 0.0485 kg
c = specific heat capacity = [tex]0.14kJ/kgK[/tex]
L = heat of vaporization = 59.2 kJ
Initial temperature of liquid mercury = [tex]T_i[/tex] = 400 K
Final temperature of mercury vapor = [tex]T_f[/tex] = 700 K
Putting in the values, we get:
[tex]Q=0.0485\times 0.14\times (629.88-400)+0.0485\times 59.2+0.0485\times 0.14\times (700-629.88)[/tex]
[tex]Q=1.56+2.87+0.476[/tex]
[tex]Q=4.91kJ[/tex]
