A 56 kg object is attached to a rope, which can be used to move the load vertically.

a. What is the tension force in the rope when the object moves upward at a constant velocity?

b. What is the tension force in the rope when the object accelerates downward at a constant

acceleration of 1.8 m/s2

c. What is the tension force in the rope when the object accelerates upward at a constant

acceleration of 1.8 m/s2

Respuesta :

Answer:

a) T=549.36N Upwards

b) T=448.56N Upwards

c) T=650.16N Upwards

Explanation:

The very first thing we can do to solve this problem is to draw a free body diagram we can use to analyze the situation (see attached picture).

On the diagram we can see there are only two forces acting on the object: the tension of the rope and the weight of the object itself.

a)

Since the object is moving at a constant speed, this means that its acceleration will be zero. So we can do a sum of forces like this:

[tex]\sum F=0[/tex]

T-W=0

T=W

T=mg

[tex]T=(56kg)(9.81m/s^{2})[/tex]

T=549.36N upwards

b)

For part b, since the object is accelerating downwards, we wil say that it's acceleration is negative, so [tex]a=-1.8m/s^{2}[/tex]

so we can do a sum of forces again:

[tex]\sum F=ma[/tex]

so

T-W=ma

T=ma +W

T=ma+mg

T=m(a+g)

and now we substitute:

[tex]T=(56kg)(-1.8 m/s^{2}+9.81 m/s^{2})[/tex]

which yields:

T=448.56N upwards (in this particular case, the tension always goes upwards)

c)

Since the object is moving upwards, we can say that its acceleration will be positive, so [tex]a =1.8m/s^{2}[/tex]

we can take the solved equation we got on the previous part of the problem, so we get:

T=m(a+g)

[tex]T =(56kg)(1.8 m/s^{2}+9.81 m/s^{2})[/tex]

which yields:

T=650.16N upwards

Ver imagen ajdonis

The tension force in the rope when the object moves upward at a constant velocity is 548.8 N.

The tension force in the rope when the object accelerates downward at a constant acceleration is 448 N.

The tension force in the rope when the object accelerates upward at a constant acceleration is 649.6 N.

The given parameters:

  • Mass of the object, m = 56 kg

The tension force in the rope when the object moves upward at a constant velocity;

T = ma + mg

at constant velocity, a = 0

T = mg

T = 56(9.8)

T = 548.8 N

The tension force in the rope when the object accelerates downward at a constant acceleration of 1.8 m/s².

T = mg - ma

T = m(g - a)

T = 56(9.8 - 1.8)

T = 448 N

The tension force in the rope when the object accelerates upward at a constant acceleration of 1.8 m/s².

T = mg + ma

T = m(g + a)

T = 56(9.8 + 1.8)

T = 649.6 N

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