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1. A sailor pulls a boat along a dock using a rope at an angle of 60.0º with the horizontal. How much work does the sailor do if he exerts a force of 255 N on the rope and pulls the boat 3.00 m?

W = FdcosO =255 x 3 x cos 60 =


2. An elephant pushes with 2000 N at an angle of 33o above the horizontal on a load of trees. It then pushes these trees for 150 m. How much work did the elephant do?


3. Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22.9 Newtons at an angle of 35o above the horizontal to drag his backpack a horizontal distance of 129 m. Determine the work done upon the backpack.


4. If 100 N force has 30o angle pulling on a 15 kg block for 5 m. What’s the work?

Respuesta :

Answer:

(1)Work done by snail is 382.5 N

(2)Work done by ELEPHANT is 25160 N

(3)Work done by HANS is 2420 N

(4)Work done on block is 433 N

Explanation:

The work done due to force F applied at an angle θ from the horizontal to the body is give by

Work done = Fscosθ where, s is distance traveled by body

Case 1: F= 255N , s= 3.00m and θ = 60.[tex]0^0[/tex]

Work done = Fscosθ = 255 x 3.00 x cos60.[tex]0^0[/tex] = 382.5N

thus work done by snail is 382.5 N

Case 2: F= 200N , s= 150m and θ = 33.[tex]0^0[/tex]

Work done = Fscosθ = 200 x 150 x cos33.[tex]0^0[/tex] = 25160N

thus work done by elephant is 25160 N

Case 3: F= 22.9N , s= 129m and θ = 35.[tex]0^0[/tex]

Work done = Fscosθ = 22.9 x 129 x cos35.[tex]0^0[/tex] = 2420N

thus work done by Hans is 2420 N

Case 4: F= 100N , s= 5m and θ = 30.[tex]0^0[/tex]

Work done = Fscosθ = 100 x 5.00 x cos30.[tex]0^0[/tex] = 433N

thus work done on block is 433 N

snehashish65

(1)  The work done by the sailor is 382.5 J.

(2)  The work done by elephant is 25160 J.

(3) The work done by Hans upon the backpack is 2420 J.

(4)  The required work done on block is 433 J.

Let us solve these questions in parts. All these questions are based on the work done. The work done due to force F applied at an angle θ from the horizontal to the body is give by,

[tex]W =F \times s \times cos \theta[/tex]

Here, s is the distance covered by the body.

(1)

Given data:

F= 255N , s= 3.00m and θ = 60.

The work done is calculated as,

W = Fscosθ

W= 255 x 3.00 x cos60 = 382.5 J.

Thus, the work done by the sailor is 382.5 J.

(2)

Given data:

F= 200N , s= 150m and θ = 33.

The work done by the elephant is calculated as,

W = Fscosθ

W= 200 x 150 x cos33. = 25160 J

Thus, the work done by elephant is 25160 J.

(3)

Given data:

F= 22.9N , s= 129m and θ = 35.

Then the work done upon the backpack is calculated as,

W= Fscosθ

W= 22.9 x 129 x cos35. = 2420 J

Thus, the work done by Hans upon the backpack is 2420 J.

(4)

Given data:

F= 100N , s= 5m and θ = 30.

The work done is calculated as,

W = Fscosθ

W= 100 x 5.00 x cos30. = 433 J

Thus, the required work done on block is 433 J.

Learn more about the work done here:

https://brainly.com/question/13662169

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