Respuesta :
Answer:
0.024 kg CaO
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Chemistry
Aqueous Solutions
- Molarity = moles of solute / liters of solution
Atomic Structure
- Reading a Periodic Tables
- Using Dimensional Analysis
Explanation:
Step 1: Define
0.41 mol CaO
2.5 M Solution
Step 2: Identify Conversions
1000 g = 1 kg
Molar Mass of Ca - 40.08 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol
Step 3: Convert
- Set up: [tex]\displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})[/tex]
- Multiply: [tex]\displaystyle 0.024114 \ kg \ CaO[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs as our lowest.
0.024114 kg CaO ≈ 0.024 kg CaO
Answer:
0.172 Kg
Explanation:
Given data:
Kg of solvent = ?
Moles of solute = 0.43 mol
Molality = 2.5 m
Solution:
Formula:
m = moles / Kg of solvent
by putting values,
2.5 m = 0.43 mol / kg of solvent
Kg of solvent = 0.43 mol / 2.5 m
Kg of solvent = 0.172 Kg