Answer:
point A is located at (-2,5) and point B is located at point (5,5), the distance between the points is 7 units. hope this helps!
The distance between the points will be 7 units. Point A is located at the point (-2, 5). Point B is located at the point (5, 5).
The formula of distance between two points is A(x₁, y₁) and B(x₂, y₂) is given by: [tex](A,B) = \sqrt{( x_{2} - x_{1} )^2 + ( y_{2} - y_{1})^2}[/tex]
We have,
Point A (-2, 5) and Point B (5, 5).
i.e.
x₁ = -2, x₂ = 5 and
y₁ = 5, y₂ = 5
Now,
Using the above mentioned formula of distance,
i.e.
Distance [tex](A,B) = \sqrt{( x_{2} - x_{1} )^2 + ( y_{2} - y_{1})^2}[/tex]
So,
Substituting values,
Distance [tex](A,B) = \sqrt{(5-(-2) )^2 + ( 5-5)^2}[/tex]
Now, simplify,
Distance [tex](A,B) = \sqrt{(7)^2 + 0}[/tex]
We get,
Distance [tex](A,B) = 7[/tex]
So, the distance between AB is 7 units.
Hence, we can say that the distance between the points will be 7 units. Point A is located at the point (-2, 5). Point B is located at the point (5, 5).
To know more about distance between the points click here
https://brainly.com/question/15958176
#SPJ2
