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What is the equation in standard form of the line that passes through the point (4, −8) and has a slope of 1/4?

A) x − 4y = 36
B) x − 4y = −28
C) x − 4y = −36
D) x − 4y = 28

Respuesta :

Answer:

Option A is correct.

Step-by-step explanation:

Given

  • The point (4, -8)
  • Slope m = 1/4

To determine

What is the equation in the standard form of the line that passes through the point (4, −8) and has a slope of 1/4.

Using the point-slope form of the line equation

[tex]y-y_1=m\left(x-x_1\right)[/tex]

where

  • m is the slope of the line
  • (x₁, y₁) is the point

substituting the values m = 1/4 and the point (4, -8)

[tex]y-y_1=m\left(x-x_1\right)[/tex]

[tex]y-\left(-8\right)=\frac{1}{4}\left(x-4\right)[/tex]

[tex]y+8=\frac{1}{4}\left(x-4\right)[/tex]

Subtract 8 from both sides

[tex]y+8-8=\frac{1}{4}\left(x-4\right)-8[/tex]

[tex]y=\frac{1}{4}x-1-8[/tex]

[tex]y=\frac{1}{4}x-9[/tex]

Writing the equation in the standard form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

so

[tex]y=\frac{1}{4}x-9[/tex]

[tex]x=4y+36[/tex]

[tex]x - 4y = 36[/tex]

Therefore, the equation in the standard form of the line that passes through the point (4, −8) and has a slope of 1/4 will be:

[tex]x - 4y = 36[/tex]

Hence, option A is correct.