The table below shows data from a survey about the amount of times students spend doing homework each week. The students were either in college or in high school:


Which of the choices below best describes how to measure the spread of this data?

A- Both spreads are best described with the IQR.

B- Both spreads are best described with the standard deviation.

C- The college spread is best described by the IQR. The high school spread is best described by the standard deviation.

D- The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

The table below shows data from a survey about the amount of times students spend doing homework each week The students were either in college or in high school class=

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Answer:

in table data from a survey about the amount of time students spend doing homework each week. The students were either in college or in high school: High Low Q1 Q3 IQR Median Mean σ

College 50 5 7.5 15 7.5 11 13.8 6.4

High School16 0 9.5 14.5 5 13 10.7 5.3 Both spreads are best described with the standard deviation.

Step-by-step explanation:

The true statement is that: (b) Both spreads are best described with the standard deviation.

Outliers

To determine the spread to use for the dataset, we start by checking for outliers using:

[tex]L = Q_1 - 1.5 \times IQR[/tex]

[tex]U = Q_3 + 1.5 \times IQR[/tex]

College

For the college, we have:

[tex]L =8 - 1.5 \times 10 = -7[/tex]

[tex]U = 18 + 1.5 \times 10 = 33[/tex]

The range of the dataset is 6 to 20.

This means that, there is no outlier in the college dataset

High School

For the high school, we have:

[tex]L =5.5 - 1.5 \times 10.5 = -10.25[/tex]

[tex]U = 16 + 1.5 \times 10.5 = 31.75[/tex]

The range of the dataset is 3 to 20.

This means that, there is no outlier in the college dataset

Since there are no outliers in both dataset, then it is best to use the standard deviation to describe the spread

Hence, both spreads are best described with the standard deviation.

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