Answer:
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = 0.0228
Step-by-step explanation:
Step(i):-
Given mean of the Population = 500
Given standard deviation of the Population = 50
Let 'X' be the random variable in normal distribution
Given X = 600
[tex]Z = \frac{x-mean}{S.D} = \frac{600-500}{50} = \frac{100}{50} =2[/tex]
Step(ii):-
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = P(z≥2)
= 0.5 - A(2)
= 0.5 -0.4772
= 0.0228
Final answer:-
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = 0.0228
