Given that,
Distance travelled, d = 3.06 m
Final velocity, v = 0.18 m/s
Average velocity of the object, V = 0.34 m/s
To find,
The acceleration of the object.
Solution,
Let t is the time in which it covers distance d. Average velocity is given by distance covered divided by time.
[tex]V=\dfrac{d}{t}\\\\t=\dfrac{d}{V}\\\\t=\dfrac{3.06}{0.34}\\\\t=9\ s[/tex]
Let a is the acceleration of the object. Using equation of motion to find it :
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.18-0}{9}\\\\a=0.02\ m/s^2[/tex]
So, the acceleration of the object is 0.02 m/s².
