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Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to report the mass truthfully). (a) What is the force constant (in N/m) of the spring in such a scale if it stretches 8.50 cm for a 12.0 kg load?

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pstnonsonjoku

Answer:

1411.8 N/m

Explanation:

From Hooke's law;

F= Ke

Where

F= force on the spring

K= force constant

e = extension

But e= 8.50 × 10^-2m

F= weight = 12.0 kg × 10 = 120 N

K = F/e = 120/8.50 × 10^-2

K= 1411.8 N/m

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