Answer:
The melting point of led is: 622.45 Fahrenheit
Step-by-step explanation:
Given that
The melting point of aluminum is 1220 degrees Fahrenheit.
Let a be the melting point of aluminum and l be the melting point of lead.
The according to given statement, we can write that
[tex]a = 1.96l[/tex]
Putting the value of a
[tex]1220=1.96l[/tex]
dividing both sides by 1.96
[tex]\frac{1220}{1.96} = \frac{1.96l}{1.96}\\l = 622.4489...[/tex]
Rounding off to nearest hundredth
[tex]l = 622.45[/tex]
Hence,
The melting point of led is: 622.45 Fahrenheit
