Respuesta :
The complete question is as follows:
Calculate the volume in liters of a [tex]3.2 \times 10^{-5} M[/tex] silver(II) oxide solution that contains 200 g of silver(II) oxide . Round your answer to significant digits.
Explanation:
Given: Molarity = [tex]3.2 \times 10^{-5} M[/tex], mass = 200 g
The number of moles is given mass divided by molar mass of substance.
Molar mass of silver(II) oxide [tex](Ag_{2}O)[/tex] is 231.735 g/mol. Hence,
No. of moles = [tex]\frac{mass}{molar mass}[/tex]
= [tex]\frac{200 g}{231.735 g/mol}[/tex]
= 0.863 moles
Molarity is the number of moles present in liter of solution. Therefore,
Molarity = [tex]\frac{no. of moles}{Volume (in L)}[/tex]
So, volume (in L) = [tex]\frac{no. of moles}{molarity}[/tex]
= [tex]\frac{0.863 mol}{3.2 \times 10^{-5}M}[/tex]
= [tex]0.269 \times 10^{5}[/tex] L
Thus, volume of given solution is [tex]0.269 \times 10^{5}[/tex] L.
