Answer:
[tex]-0.75[/tex] [tex]m/s^{2}[/tex]
Explanation:
Given: A driver slows from [tex]24[/tex] [tex]m/s[/tex] to [tex]15[/tex] [tex]m/s[/tex] in [tex]12[/tex] seconds.
To find: The acceleration of the automobile.
Solution: We have,
Initial velocity, [tex]u=24[/tex] [tex]m/s[/tex].
Final velocity, [tex]v=15[/tex] [tex]m/s[/tex].
Time, [tex]t=12[/tex] seconds.
We know that acceleration, [tex]a=\frac{v-u}{t}[/tex]
[tex]\Rightarrow a=\frac{15-24}{12}=\frac{-9}{12}=\frac{-3}{4}=-0.75[/tex] [tex]m/s^{2}[/tex].
Hence, the acceleration of the automobile is [tex]-0.75 m/s^{2}[/tex]. The automobile is slowing down with an acceleration of [tex]0.75 m/s^{2}[/tex].
