Answer:
0.02 M
Explanation:
Given data:
Mass of sodium carbonate = 1.8 g
Volume of water = 862 cm³ (862/1000 = 0.862 L)
Concentration = ?
Solution:
Formula:
Concentration = number of moles / volume in L
Number of moles of sodium carbonate:
Number of moles = mass/molar mass
Number of moles = 1.8 g/ 106 g/mol
Number of moles = 0.02 mol
Concentration:
c = 0.02 mol / 0.862 L
c = 0.02 M
