Respuesta :

kritika3375

Step-by-step explanation:

first term (t1) = 6 (a)

Second term (t2) = - 18

Common ratio (r) = t2/ t1 = - 18 / 6 = -3

Now

14th term (t14)

=

[tex]a {r}^{14 - 1} [/tex]

[tex]6 \times ( - 3)^{13} [/tex]

= 6 X - 1594323

= 9565938

adioabiola

The 14th term of the geometric sequence 6, -18,54, ... is -9,565,938

Geometric series

Given:

6, -18, 54, ...

  • First term, a = 6

Common ratio, r = a2 ÷ a1

= -18 / 6

= -3

  • nth term of a geometric series = ar^n -1

14th term = 6 × -3^(14-1)

= 6 × -3^13

= 6 × -1,594,323

= -9,565,938

Therefore, 14th term of the geometric sequence 6, -18,54, ... is -9,565,938

Learn more about geometric series:

https://brainly.com/question/2899779

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