Heather has a coin that has a 60\%60%60, percent chance of showing heads each time it is flipped. She is going to flip the coin 555 times. Let XXX represent the number of heads she gets. What is the probability that she gets exactly 333 heads? You may round your answer to the nearest hundredth.

Respuesta :

Answer:

(5/3) (0.60)^3(0.40)^2

Step-by-step explanation:

Using the binomial distribution, it is found that there is a 0.3456 = 34.56% probability that she gets exactly 3 heads.

For each coin flipped, there are only two possible outcomes, either it is heads, or it is tails. The result of a coin flip is independent of any other coin flip, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The coin is flipped 5 times, hence [tex]n = 5[/tex].
  • 60% of the time, it comes up heads, hence [tex]p = 0.6[/tex].

The probability is P(X = 3), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456[/tex]

0.3456 = 34.56% probability that she gets exactly 3 heads.

A similar problem is given at https://brainly.com/question/21270423