Given:
The Population of Brownsville is 20,000 in year 2010.
Consider the population function
[tex]P(t)=20000(1.15)^t[/tex]
To find:
The population in 2012.
Solution:
The population function of Brownsville is
[tex]P(t)=20000(1.15)^t[/tex]
The Population of Brownsville is 20,000 in year 2010.
So, the given function P(t) represents the population of Brownsville after t years of 2010.
2012 is 2 years after 2010.
Putting t=2 in P(t), we get
[tex]P(2)=20000(1.15)^2[/tex]
[tex]P(2)=20000(1.3225)[/tex]
[tex]P(2)=26450[/tex]
Therefore, the Population of Brownsville is 26,450 in year 2012.
