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the brakes applied to a car produces an acceleration of 6m/s^2 in the opposite direction to the motion. if the car takes 2s to stop after the application of brakes. calculate the distance it travels during this time .

Respuesta :

NusrathC

Answer:

acceleration= -6ms^-2

Explanation:

[tex]v = u + at \\ 0 = u + ( - 6 \times 2) \\ u = 12m {s}^{ - 1} [/tex]

distance

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 12 \times 2 + \frac{1}{2} \times ( - 6) \times {2}^{2} \\ s = 12m[/tex]

therefore distance = 12m

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