Answer:
Step-by-step explanation:
Decay is defined by the function as,
f(t) = [tex](1-\frac{r}{n} )^{nt}[/tex]
Here, r = rate of decay
t = duration of decay Or time (In years)
n = Number of times of decay in a year
Decay every 2 years over a period of t years,
f(t) = [tex](1-\frac{r}{\frac{1}{2}})^{\frac{1}{2}\times t}[/tex]
= [tex](1-2r)^\frac{t}{2}[/tex]
Therefore, [tex]f(t) = (0.75)^\frac{t}{2}[/tex] will be the answer.
Decay 2 times a year over a period of t years,
f(t) = [tex](1-\frac{r}{2})^{2t}[/tex]
Therefore, [tex]f(t)=(0.9306)^{2t}[/tex] will be the answer.
Decay once per year over a period of t years,
f(t) = [tex](1-\frac{r}{1})^t[/tex]
= [tex](1-r)^t[/tex]
Therefore, [tex]f(t)=(1-r)^t[/tex] will be the answer.
