Given:
The product of [tex]\dfrac{9}{5}[/tex] and [tex]8\dfrac{1}{4}[/tex] greater than 5.
To find:
By how much the product of [tex]\dfrac{9}{5}[/tex] and [tex]8\dfrac{1}{4}[/tex] greater than 5.
Solution:
First we need to find the product of [tex]\dfrac{9}{5}[/tex] and [tex]8\dfrac{1}{4}[/tex].
[tex]\text{Product}=\dfrac{9}{5}\times 8\dfrac{1}{4}[/tex]
[tex]\text{Product}=\dfrac{9}{5}\times \dfrac{8(4)+1}{4}[/tex]
[tex]\text{Product}=\dfrac{9}{5}\times \dfrac{33}{4}[/tex]
[tex]\text{Product}=14.85[/tex]
Now subtract 5 from the product.
[tex]14.85-5=9.85[/tex]
Therefore, the product of [tex]\dfrac{9}{5}[/tex] and [tex]8\dfrac{1}{4}[/tex] is 9.85 greater than 5.
