Answer:
a) Average speed = 200 Km/hr
b) Average velocity = 0 m/s
c) Total distance = 800 Km
d) Total displacement = 0 Km
Explanation:
a) Let the speed of the plane from Addis Ababa to Gamble be represented by [tex]S_{1}[/tex], and from Gamble to Addis Ababa by [tex]S_{2}[/tex].
Average speed = [tex]\frac{S_{1} + S_{2} }{2}[/tex]
[tex]S_{1}[/tex] = [tex]\frac{distance}{time}[/tex] = [tex]\frac{400}{2}[/tex]
= 200 Km/hr
[tex]S_{2}[/tex] = [tex]\frac{distance}{time}[/tex] = [tex]\frac{200}{1}[/tex]
= 200 Km/hr
Average speed = [tex]\frac{200 + 200}{2}[/tex]
= 200 Km/hr
b) Velocity = [tex]\frac{displacement}{time}[/tex]
Average velocity = [tex]\frac{total displacement}{total time taken}[/tex]
Since the plane flies from Addis Ababa to Gamble, then back to Addis Ababa, its total displacement is zero.
So that,
Average velocity = 0 m/s
c) Total distance = 400 Km + 400 Km
= 800 Km
d) Total displacement = 400 Km + (-400 Km)
= 0 Km
