Answer:
1.75M
Explanation:
The problem deals with finding the molarity of the given compound.
The compound is:
Na₂SO₄.10H₂O
Mass of the compound = 10.5kg = 10500g
Volume of the compound = 18.6L
Molarity is the number of moles of solute in a solution;
Molarity = [tex]\frac{number of moles }{volume}[/tex]
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of Na₂SO₄.10H₂O = 2(23) + 32 + 4(16) + 10[2(1) + 16]
= 322g/mol
Now;
Number of moles = [tex]\frac{10500}{322}[/tex] = 32.6mole
So;
Molarity = [tex]\frac{32.6}{18.6}[/tex] = 1.75M
