Answer:
solutions are not real
Step-by-step explanation:
Use the discriminant to determine the type of solutions
Given ax² + bx + c, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then solutions are real and distinct
• If b² - 4ac = 0 then solutions are real and equal
• If b² - 4ac < 0 then solutions are not real
For 2x² + 4x + 4
with a = 2, b = 4 , c = 4 , then
b² - 4ac = 4² - (4 × 2 × 4) = 16 - 32 = - 16
Since b² - 4ac < 0 then solutions are not real
