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a sample of gas is initially at STP. what would the pressure be if the temperature were increased to 819C ?​

Respuesta :

The pressure would be 4 atm

Further explanation

Given

gas at STP(1 atm, 273 K)

T₂ = 819 °C + 273 =1092 K

Required

The peressure

Solution

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

[tex]\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]

P₂ = (P₁.T₂)/T₁

P₂ = (1 atm x 1092 K)/273 K

P₂ = 4 atm