Answer:
The equation of the line that passes through the point (1,3) and has a slope of -32.
[tex]y=-32x+35[/tex]
Please check the attached graph too.
Step-by-step explanation:
Given
The point-slope form:
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where
In our case:
m = -32
(x₁, y₁) = (1, 3)
substituting m = -32 and (x₁, y₁) = (1, 3) in the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-3=-32\left(x-1\right)[/tex]
Add 3 to both sides
[tex]y-3+3=-32\left(x-1\right)+3[/tex]
Simplify
[tex]y=-32x+35[/tex]
Therefore, the equation of the line that passes through the point (1,3) and has a slope of -32.
[tex]y=-32x+35[/tex]
Please check the attached graph too.