Answer:
The equation of the line with a slope of 1/5 that passes through the point (10,9) is:
- [tex]y=\frac{1}{5}x+7[/tex]
Step-by-step explanation:
Given
Slope = m = 1/5
Point (10, 9)
To Determine
An equation of the line with a slope of 1/5 that passes through the point (10,9).
We know that the point-slope form of the line equation is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where
- m is the slope of the line
substituting the values m = 1/5 and the point (10, 9) in the equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-9=\frac{1}{5}\left(x-10\right)[/tex]
Add 9 to both sides
[tex]y-9+9=\frac{1}{5}\left(x-10\right)+9[/tex]
[tex]y=\frac{1}{5}x-2+9[/tex]
[tex]y=\frac{1}{5}x+7[/tex]
Therefore, the equation of the line with a slope of 1/5 that passes through the point (10,9) is:
- [tex]y=\frac{1}{5}x+7[/tex]
