Please Help! Dimitri bought a cylindrical clay flowerpot that holds approximately 15 gallons of dry soil (1 gallon ≈ 0.15 cubic feet). The radius of the pot is 9 inches. What is the height of the flowerpot to the nearest tenth of a foot? Show your work.

Respuesta :

Nayefx

Answer:

[tex]\huge\colorbox{blue}{h$\approx$1.3 foot }[/tex]

Step-by-step explanation:

we are given volume and redious

but r is in inches and V is in gallons

so we have to convert V into inches unit

[tex] \sf\displaystyle 1\: cubic\: foot=1728 \: cubic\: inches[/tex]

first convert gallon to cubic foot

[tex] \sf\displaystyle 15\times 0.15\: (\text{since 1 gallon=0.15 cubic feet}) \\ \displaystyle \: = 2.25[/tex]

now convert cubic feet to cubic inches:

[tex]\sf\displaystyle 2.25\times 1728 \\ = 3888[/tex]

now we need a little algebra to figure out h

[tex]V_{cylinder}=\pi r^2 h[/tex]

substitute the value of V and r:

[tex] \displaystyle \: \pi \times {9}^{2} \times h = 3888[/tex]

simplify square:

[tex] \displaystyle \: \pi \times 81 \times h = 3888[/tex]

divide both sides by 81:

[tex] \displaystyle \: \frac{ \pi \times 81 \times h}{81} = \frac{ 3 888}{81} \\ \pi \times h = 48[/tex]

divide both sides by π:

[tex] \displaystyle \: \frac{\pi \times h}{\pi} = \frac{48}{\pi} \\ \: h \approx 15.3[/tex]

12 inches = 1 foot

15.3 " =15.3/12

≈1.3 foot