Question:
Triangle ABC, with coordinates A(2, 3), B(3, 5), C(7, 4), is dilated by a scale factor of 2. What are the coordinates of the dilated figure, triangle A′B′C′?
Answer:
[tex]A' =(4,6)[/tex]
[tex]B' = (6,10)[/tex]
[tex]C' = (14,8)\\[/tex]
Step-by-step explanation:
Given
[tex]A = (2,3)[/tex]
[tex]B = (3,5)[/tex]
[tex]C =(7,4)[/tex]
[tex]n = 2[/tex] -- Scale factor
Required
Determine the coordinates of A'B'C'
This is calculated by:
[tex]A'B'C' = n * ABC[/tex]
For A':
Substitute values for n and A
[tex]A' =n * A[/tex]
[tex]A' =2 * (2,3)[/tex]
[tex]A' =(4,6)[/tex]
For B':
Substitute values for n and B
[tex]B' = n * B[/tex]
[tex]B' = 2 * (3,5)[/tex]
[tex]B' = (6,10)[/tex]
For C':
Substitute values for n and C
[tex]C' = n * C[/tex]
[tex]C' = 2 * (7,4)[/tex]
[tex]C' = (14,8)[/tex]
