Answer:
[tex]\huge\boxed{\sf No.\ of\ atoms = 1.4 * 10^{20} \ atoms}[/tex]
Explanation:
Given Data:
Volume = v = 5000 cm³ = 0.005 m³
Density of CO₂ at RTP = 1.98 kg / m³
Molar Mass = M = 12 + 16 * 2 = 44 g / mol
Avogadro's No. = [tex]\sf N_{A}[/tex] = 6.023 * 10²³ mol⁻¹
Required:
Number of atoms = ?
Solution:
We know that:
No. of moles (n) = mass in grams / molar mass ∴ Mass = Density * Volume
n = D * v / M
n = 1.98*0.005 / 44
n = 0.000225
Now, Finding the number of atoms
No. of atoms = No. of moles * Avogadro's Number
No. of atoms = 0.000225 * 6.023 * 10²³
No. of atoms = 0.0014 * 10²³
No. of atoms = 1.4 * 10²⁰ atoms
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
