Answer:
The larger integer is [tex]4[/tex].
Step-by-step explanation:
Given: Two times the smaller of two consecutive integers is equal to [tex]2[/tex] more than the larger.
To find: The larger integer.
Solution:
Let the two consecutive integers be [tex]x[/tex] and [tex]x+1[/tex], where the smaller integer is [tex]x[/tex] and larger integer is [tex]x+1[/tex].
Now, according to question.
Two times the smaller integer [tex]=[/tex] [tex]2[/tex] more than the larger integer.
[tex]\implies 2x=x+1+2[/tex]
[tex]\implies 2x-x=3[/tex]
[tex]\implies x=3[/tex]
So, the smaller integer is [tex]3[/tex], and the larger integer is [tex]3+1=4.[/tex]
Hence, the larger integer is [tex]4.[/tex]
