Answer:
The volume will be 30759mL
Explanation:
To solve this question we need to use the combined gas law:
P₁V₁/T₁ = P₂V₂/T₂
Where P is pressure, V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas
Computing the values (STP are 1atm and 273.15K):4
P₁ = 1atm
V = 6500mL
T₁ = 273.15K
P₂ = 0.25atm
V₂ = ?
T₂ = 273.15K + 50°C = 323.15K
1atm*6500mL/273.15K = 0.25atmV₂/323.15K
V₂ = 30759mL
