Answer:
11 molecules of CH4.
23 atoms of C is the leftover.
Explanation:
Hello!
In this case, for the formation of methane:
[tex]C+2H_2\rightarrow CH_4[/tex]
We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:
[tex]molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2[/tex]
Thus, the formed molecules of methane are computed below:
[tex]molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4[/tex]
In such a way, the leftover of carbon atoms are:
[tex]atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C[/tex]
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