Answer:
See explanations below
Step-by-step explanation:
Given the polynomial function
P(x) = X^2+3x-10
To check whether x-2 and x+5 are factor, we will find x and then show that P(x) = 0
For x-2
x - 2 = 0
x =2
P(2) = 2²+3(2)-10
P(2) = 4+6 -10
P(2) = 10-10
P(2) = 0
Since the remainder is zero, hence x-2 is a factor of the polynomial
Similarly for x+5;
x+5 = 0
x = -5
P(-5) = (-5)²+3(-5)-10
P(-5) = 25-15-10
P(-5) = 10-10
P(-5) = 0
This also shows that x+5 is a factor
