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Find the magnitude of the velocity of the of the chain when 5.58 m of the chain is hanging vertically. Answer in units of m/s.

Respuesta :

abidemiokin

Answer:

10.46m/s

Explanation:

Given

Distance = 5.58m

Required

magnitude of the velocity'

Using the equation of motion expressed as

v² = u² + 2gS

v² = 0  +2(9.8)(5.58)

v² = 109.368

v= √109.368

v = 10.46m/s

Hence the magnitude of the velocity of the of the chain is 10.46m/s

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