Respuesta :
The given question is incomplete. The complete question is:
Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer: 0.0484 g
Explanation:
[tex]Q=I\times t[/tex]
where Q= quantity of electricity in coloumbs
I = current in amperes = 0.920 A
t= time in seconds = 47.0 sec
[tex]Q=0.920A\times 47.0s=43.24C[/tex]
[tex]AgNO_3\rightarrow Ag^++NO_3^-[/tex]
[tex]Ag^++e^-\rightarrow Ag[/tex]
96500 Coloumb of electricity electrolyzes 1 mole of Ag
43.24 C of electricity deposits =[tex]\frac{1}{96500}\times 43.24=0.00045moles[/tex] of Ag
[tex]\text{ mass of Ag}={\text{no of moles}\times {\text{Molar mass}}=0.00045mol\times 108g=0.0484g[/tex]
Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g
