The specific heat of the substance : c = 1.044 J/g °C
J/g °C
Further explanation
Given
Heat absorbed by substance = 989 J
m = mass = 37.9 g
Δt = Temperature difference : 25 °C
Required
The specific heat
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
989 = 37.9 x c x 25
c = 989 : (37.9 x 25)
c = 1.044 J/g °C
