The specific heat of the substance : c = 0.235 J/g °C
Further explanation
Given
Heat absorbed by substance = 419.7 J
m = mass = 23.5 g
Δt = Temperature difference : 76 °C
Required
The specific heat
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
419.7 = 23.5 x c x 76
c = 419.7 : (23.5 x 76)
c = 0.235 J/g °C
