Respuesta :

Space

Answer:

2.6299 g NaCl

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Stoichiometry

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN} FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

[Given] 2.43306 g FeCl₃

Step 2: Identify Conversions

[RxN] 1 mol FeCl₃ = 3 mol NaCl

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na - 22.99 g/mol

Molar Mass of FeCl₃ = 55.85 + 3(35.45) = 162.2 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

Step 3: Stoichiometry

  1. Set up:                               [tex]\displaystyle 2.43306 \ g \ FeCl_3(\frac{1 \ mol \ FeCl_3}{162.2 \ g \ FeCl_3})(\frac{3 \ mol \ NaCl}{1 \ mol \ FeCl_3})(\frac{58.44 \ g \ NaCl}{1 \ mol \ NaCl})[/tex]
  2. Multiply/Divide:                                                                                                [tex]\displaystyle 2.62986 \ g \ NaCl[/tex]

Step 4: Check

Follow sig fig rules and round. We need 5 sig figs (instructed).

2.62986 g NaCl ≈ 2.6299 g NaCl

Answer:

2.6299

Explanation:

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