A PARALLEL line has the same angular coeficient, so:
[tex]f(x) = 2x+b[/tex]
[tex]f(4) = 5[/tex]
[tex]5 = 2\cdot 4 +b[/tex]
[tex]b = 5-8[/tex]
[tex]b = -3[/tex]
The line asked is:
[tex]f(x) = 2x-3[/tex]
Answer:
-2x+y=-3
Step-by-step explanation:
Choose a point (4,5) that the parallel line will pass through.
Find the slope m=2
To find an equation that is parallel to y=2x-4 the slopes must be equal. Using the slope of the equation, find the parallel line using the point-slope formula.
y-y1=m(x-x1) if m=2 and x1=4 and y1=5
y-5=2(x-4)
y-5=2x-8
Solve for y --- > y=2x-3
-2x+y=-3
(-2x+y=-3)*-1
2x-y=3
