Answer:
It can hold up to [tex]1.256ft^3[/tex] of waste
Step-by-step explanation:
Given
[tex]D = 1.5ft[/tex] -- Diameter
[tex]h = 1.6ft[/tex] -- height
Required
Determine the amount of waste it can hold
This simply means that we calculate the volume of the cylindrical container.
And this is calculated using:
[tex]Volume = \pi r^2h[/tex]
Where
[tex]\pi = 3.14[/tex]
and
[tex]r = \frac{D}{2}[/tex]
[tex]r = \frac{1.5}{2}[/tex]
[tex]r = 0.75[/tex]
So, we have:
[tex]Volume = 3.14 * 0.5^2 * 1.6[/tex]
[tex]Volume = 1.256ft^3[/tex]
Hence, it can hold up to [tex]1.256ft^3[/tex] of waste
The amount of waste a cylinder can hold nearest to the whole number is 3 cubic feet.
A cylinder is a closed solid that has two parallel circular bases connected by a curved surface.
A cylindrical hazardous waste container has a diameter of 1.5 feet and a height of 1.6 feet.
The amount of waste a cylinder can hold will be given by the volume of the cylinder.
The volume of the cylinder will be
[tex]\rm Volume = \dfrac{\pi}{4} d^2 h[/tex]
We have
d = 1.5 ft
h = 1.6 ft
Then
[tex]\rm Volume = \dfrac{\pi}{4} * 1.5^2 * 1.6\\\\\rm Volume = \dfrac{\pi}{4} *2.25 * 1.6\\\\\rm Volume = 2.82 \approx 3 \ ft^3[/tex]
More about the cylinder link is given below.
https://brainly.com/question/3692256
